Question

How do you factor `3n ^ { 2} + 21n - 24`?

Answer 1

(x - 1)(3x + 24)

Explanation:

`y = 3n^2 + 21n - 24`.
Because a + b + c = 0, use shortcut.
The 2 factors are:
(x - 1) and `(x + c/a = x + 24/3)`
`y = 3(x - 1)(x + 24/3) = (x - 1)(3x + 24)`

Answer 2

`3(n-1)(n+8)`

Explanation:

Initially you can factor a 3 out of everything giving you :

`3(n^2+7n-8)`

Then simply factor `(n^2+7n-8)` which gives you :

`3(n-1)(n+8)`