How do you solve #5+ 3x = - 4x + 40#?

1 Answer
Jul 28, 2017

See a solution process below:

Explanation:

Step 1) Subtract #color(red)(5)# and add #color(blue)(4x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#5 + 3x - color(red)(5) + color(blue)(4x) = -4x + 40 - color(red)(5) + color(blue)(4x)#

#5 - color(red)(5) + 3x + color(blue)(4x) = -4x + color(blue)(4x) + 40 - color(red)(5)#

#0 + (3 + color(blue)(4))x = 0 + 35#

#7x = 35#

Step 2) Divide each side of the equation by #color(red)(7)# to solve for #x# while keeping the equation balanced:

#(7x)/color(red)(7) = 35/color(red)(7)#

#(color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7)) = 5#

#x = 5#