What is the Cartesian form of #(49,(2pi)/4)#?

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Answer 1 · 2017-07-28T16:12:27

#(0,49)#

We're asked to find the Cartesian (rectangular) form of a polar coordinate.

We can use the following two equations:

#x = rcostheta#

#y = rsintheta#

Here,

Thus, we have

#x = 49cos(pi/2) = color(red)(0#

#y = 49sin(pi/2) = color(blue)(49#

The coordinate point is therefore

#(color(red)(0), color(blue)(49))#