How do you graph #y=3-x#?

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Answer 1 · 2017-07-30T11:57:20

See a solution process below:

Substitute some points for #x# to obtain corresponding values for #y#. Such as:

#x = -10# Then #y = 3 - -10 = 3 + 10 = 13# gives: #(-10, 13)#

#x = -5# Then #y = 3 - -5 = 3 + 5 = 8# gives: #(-5, 8)#

#x = 0# Then #y = 3 - 0 = 3# gives: #(0, 3)#

#x = 5# Then #y = 3 - 5 = -2# gives: #(5, -2)#

#x = 10# Then #y = 3 - 10 = -7# gives: #(10, -7)#

Now, plot the points and draw a line through the points:

graph{y = 3 - x [-20, 20, -10, 10]}