Step 1) Add #color(red)(5/8)# to each side of the equation to isolate the #n# term while keeping the equation balanced:
#5/4n - 5/8 + color(red)(5/8) = 2/8 + color(red)(5/8)#
#5/4n - 0 = (2 + color(red)(5))/8#
#5/4n = 7/8#
Step 2) Multiply each side of the equation by #color(red)(4)/color(blue)(5)# to solve for #n# while keeping the equation balanced:
#color(red)(4)/color(blue)(5) xx 5/4n = color(red)(4)/color(blue)(5) xx 7/8#
#cancel(color(red)(4))/cancel(color(blue)(5)) xx color(blue)(cancel(color(black)(5)))/color(red)(cancel(color(black)(4)))n = cancel(color(red)(4))/color(blue)(5) xx 7/(color(red)(cancel(color(black)(8)))2)#
#n = 7/(5 xx 2)#
#n = 7/10#