How do you solve #4x + 4= 15- 7x#?

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Answer 1 · 2017-07-30T20:28:40

#x = 1#

Re-arrange to have all the #x# terms on one side and the number terms on the other.

ADD #color(magenta)(7x)# to both sides and SUBTRACT #color(blue)(4)# from both sides.

#4x+4 = 15-7x#

#4xcolor(magenta)(+7x)+4 color(blue)(-4)= 15color(blue)(-4)-7xcolor(magenta)(+7x)#

This simplifies to what we want:

#4x+7x = 15-4#

#11x =11" "larr div 11# on both sides

#x = 1#