What is the equation of the line that goes through #(2, 0)# and is parallel to #y=2/3x#?

1 Answer
Tsepi
Jul 30, 2017

y=#(2/3)x-4/3#

Explanation:

Since the lines are parallel,they wll have the same gradient. Now using the equation of the line given two pints, #y-y1=m(x-x1)#, substitute the values: #y-0=2/3(x-2)#. This gives #y=(2/3)x-4/3#

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