How do you write #-2 5/6# as an improper fraction?

1 Answer
Jul 30, 2017

See two solution processes below:

Explanation:

Process 1

Rewrite the mixed number as:

#-(2 + 5/6) => -([6/6 xx 2] + 5/6) => -(12/6 + 5/6) = #

#-(12 + 5)/6 => -17/6#

Process 2

  • Multiply the integer by the denominator: #2 xx 6 = 12#

  • Add this to the numerator: #12 + 5 = 13#

  • Put this over the denominator: #17/6#

  • Put the sign back in: #-17/6#