Question

Question #9d584

Answer 1

`r=atanΘ/cosΘ+bsecΘ+c` where `y=ax^2+bx+c`

Explanation:

It depends on the original parabola. To name one, we will use `y=-x^2+10x`, which looks like this: To convert from rectangular to polar, we use the equations, `x=rcosΘ` and `y=rsinΘ`
Substitute x and y for their respective values:
`r sinΘ=-(r cosΘ)^2+10r cos Θ`
Solve for r:
`r sinΘ=-r^2cos^2Θ+10rcosΘ`
`-sinΘ+10cosΘ=rcos^2Θ`
`r=-tanΘ/cosΘ+10secΘ`