Question

Question #4e4a9

Answer 1

`106.67` ml of water to be added.

Explanation:

Let `x` ml of water is added to dilute the acd solution.

Acid content in `35%` acid solution is `80 * 0.35 = 28` ml

After adding , total quantity of `15%` acid solution is `80 +x` ml

Acid content in `15%` acid solution is `(80+x) * 0.15` ml

Quantity of acid remains same before and after dilution.

`:. (80+x) * 0.15 =28 or 80 +x = 28/0.15 = 186 2/3`

`x = 186 2/3 - 80 = 106 2/3 ~~ 106.67` ml

`106.67` ml of water to be added [Ans]