Question

How do you solve `6(x+3)=48` using the distributive property?

Answer 1

`x=5`

Explanation:

`"multiply the terms in the bracket by 6"`

`rArr6x+18=48`

`"subtract 18 from both sides"`

`6xcancel(+18)cancel(-18)=48-18`

`rArr6x=30`

`"divide both sides by 6"`

`(cancel(6) x)/cancel(6)=30/6`

`rArrx=5`

`color(blue)"As a check"`

substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`6(5+3)=6xx8=48=" right side"`

`rArrx=5" is the solution"`