How do you solve #4x - 8= 7x + 1#?

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Answer 1 · 2017-08-01T01:38:25

#x=-3#

#4x-8=7x+1#

Subtract #4x# from each side.

#4x-4x-8=7x-4x+1#

#-8=3x+1#

Subtract #1# from each side.

#-8-1=3x+1-1#

#-9=3x#

Divide both sides by #3#.

#-9/3=(3x)/3#

#-(3cancel9)/(1cancel3)=(cancel3x)/cancel3#

#-3=x# or #x=-3#