How do you solve #( z - 4) ( z + 6) = 0#?

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Answer 1 · 2017-08-01T14:25:44

See a solution process below:

To solve this, equation each term on the left to #0# and solve for #z#:

Solution 1

#z - 4 = 0#

#z - 4 + color(red)(4) = 0 + color(red)(4)#

#z - 0 = 4#

#z = 4#

Solution 2

#z + 6 = 0#

#z + 6 - color(red)(6) = 0 - color(red)(6)#

#z + 0 = -6#

#z = -6#

The Solutions Are:

#z = 4#

#z = -6#