What is the standard form of y= -(x+5)^2(-x-1)?

1 Answer
Aug 2, 2017

y= x^3 +11x^2 +25x + 35

Explanation:

y=-(x+5)^2(-x-1)

Factor the negative sign out of the second term:
y=-(x+5)^2(-1)(x+1)

y=(x+5)^2(x+1)

Distribute each term to expand:
y= (x^2+10x+25)(x+1)

y= (x^3+x^2) + (10x^2+10) + (25x+25)

Combine like terms to get standard form:
y= x^3 +11x^2 +25x + 35