Question

Question #78ee5

Answer 1

See below.

Explanation:

The static friction force is given by `mu_s m_1g` and the applied force is `m_2 g`

Now

`m_2g - mu_s m_1 g = (m_2-mu_s m_1) g = (12-0.43*45)g = -7.35g`

so block 1 remains stopped, because the tension induced by block 2 (`m_2 g`) is less than the static friction force `mu_s m_1g`