How do you differentiate $f(x)=sinx(tanx)$ ?

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Answer 1 · 2017-08-04T14:04:12

$f'(x) = sinx + secxtanx$

$f(x) = sinx tanx$

In order to find $f'$ , use the product rule:

$(fg)' =gf'+fg'$

$sinx' = cosx$

$tanx'=sec^2x$

$f'(x) = cosxtanx + sec^2xsinx=cosxsinx/cosx+(sinxsecx)secx=sinx+secxtanx$

How do you differentiate f(x)=sinx(tanx)f(x)=sinx(tanx)?