What is the new pressure of a gas under #1112*"psi"# with a volume of #6.53*L# that is expanded to a volume of #12.45*L#?

1 Answer
anor277
Aug 4, 2017

Well #P_1V_1=P_2V_2# according to old #"Boyle's Law"#.

Explanation:

Given the proportionality, we could use any units of pressure, and volume, i.e. #"psi"#, or #"pints"#, or #"gallons"# as Boyle, working in the 17th century, undoubtedly did.

And so #P_2=(P_1V_1)/V_2=(1112*"psi"xx6.53*L)/(12.45*L)=??"psi"#

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