How do you reduce #\frac{60}{840}#?

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Answer 1 · 2017-08-05T14:15:22

#=1/14#

If you are trying to simplify a fraction and you do not know the HCF, you can simplify one step at a time.

#60/840" "larr (div10)/(div10)#

#= 6/84" "larr (div 2)/(div 2)#

#= 3/42" "larr (div3)/(div3)#

#=1/14#

The order is which you simplify does not matter at all.
I could also have simplified by #12# at the start.

#60/840" "larr(div12)/(div12)#

#=5/70" "larr (div5)/(div5)#

#= 1/14#