How do you find the values of #theta# given #tantheta=sqrt3#?
1 Answer
Aug 5, 2017
Explanation:
#"given "tantheta=sqrt3#
#rArrtheta=tan^-1(sqrt3)=pi/3#
#"since the tangent function is periodic"#
#"we can generalise the solution as"#
#theta=pi/3+npi,n inZZ#
