Differential equation vector field for #dy/dx = (x + 1) (y + 1) (1 - y)^2# ?
1 Answer
Aug 6, 2017
See below.
Explanation:
With the commands
f[x_, y_] := (x + 1) (y + 1) (1 - y)^2
StreamPlot[{1, f[x, y]}, {x, -2, 2}, {y, -2, 2}]
in Mathematica
