How do you solve #\frac { x - 3} { 2} - \frac { x - 2} { 5} = 5#?

1 Answer
Aug 7, 2017

#x = 61/3#

Explanation:

If an EQUATION has fractions, you can get rid of the denominators by multiplying each term by the LCD to cancel them.

#(color(blue)(cancel10^5xx)(x-3))/cancel2-(color(blue)(cancel10^2xx)(x-2))/cancel5 =color(blue)( 10xx)5" "larr color(blue)(xx 10)#

#5(x-3) -2(x-2) =50" "larr# no fractions, solve for #x#

#" "5x-15-2x+4 =50#

#color(white)(xxxxxwww)3x -11 =50#

#color(white)(xxxxzzzzzxwww)3x =61#

#color(white)(xxxxzzz.zzxwww)x =61/3#