How do you solve #-71= - 5( 2r + 3) - 6#?

1 Answer
Aug 7, 2017

r=5

Explanation:

First of all, distribute -5 through the parenthesis

#=> -71 = -10r-15-6 => -71 = -10r-21#

Then, change #-21# side and don't forget to change its sign !

#=> -71+21 = -10r => -50 = -10r#

Then, you divide both side by #-10#

#(-50)/(-10) = (-10r)/(-10)#

So #5 = r# (or #r = 5#)