How do you solve #(x+7)/(x-4)<0#?
4 Answers
Explanation:
For
An
Proof:
However, if top and bottom are negative, it will be positive, and any
The solution is
Explanation:
Let
We can build the sign chart
Therefore,
graph{(x+7)/(x-4) [-41.1, 41.14, -20.54, 20.55]}
Explanation:
Given:
#(x+7)/(x-4) < 0#
Note that since the linear expressions
For large positive or negative values of
graph{(y-(x+7)/(x-4))(x-3.99+y*0.0001) = 0 [-19.55, 20.45, -10.12, 9.88]}
The answer is
Explanation:
First we have to calculate the domain of the rational expression. As the denominator cannot be zero, the excluded values are:
Now we can solve the inequality.
#(x+7)/(x-4)<0#
We can change the rational inequality to quadratic inequality by multiplying it by the square of the denominator:
#(x+7)(x-4)<0#
If we graph the quadratic function:
graph{(x-4)*(x+7) [-36.52, 36.52, -18.22, 18.35]}
we see that it takes negative values for