Question

Question #e40ab

Answer 1

`2400 A/sec`

Explanation:

As everyone knows that induced emf in parallel inductors is same even they holds different inductance values.

We know that,

`E= -N (phi)/t`

`E= -N ((phi)/t)(i/i)`

`E=-(N(phi/i))(i/t)`

`E=Li/t` ##

[`'.'` `L=(phiN)/t`]

Let rate of change of current be R.

`:.E=LR` `---->(1)`

From equation (1)

Voltage across inductor having inductance L & 2L respectively,

`V_L=LR_1` `---->(2)`

`V_(2L)=2LR_2` `----->(3)`

since voltage induced in parallel inductors is same, hence

`LR_1=2LR_2`

`R_1=2R_2`

since ,
`R_2= 1200 A/sec`

hence

`R_1= 2400 A/sec`