The velocity of a particle moving along x - axis is given as #v = x^2 - 5x + 4#(in m/s), where x denotes the x-coordinate of the particle in meters. Find the magnitude of acceleration of the particle when the velocity of particle is zero?
A: #0m/s^2#
B: #2m/s^2#
C: #3m/s^2#
D: None of the above
A:
B:
C:
D: None of the above
1 Answer
Aug 8, 2017
A
Explanation:
Given velocity
Acceleration
#:.a=d/dt(x^2−5x+4)#
#=>a=(2x(dx)/dt−5(dx)/dt)#
We also know that
#=>a=(2x −5)v#
at