Question

How do you solve the quadratic using the quadratic formula given `x^2-4x-7=0`?

Answer 1

`x=5.31662479vvx=-1.31662479`

Explanation:

`x^2-4x-7=0`
First you calculate the discriminant.

`D=(-4)^2 -4*1*-7=16+28=44` (`D=b^2-4*a*c`)

Then you use the general formula `x=(-b+-sqrtD)/(2a)`

Which gives: `x= (4+- sqrt44)/(2*1)= x=5.31662479vvx=-1.31662479`