How do you simplify #\frac { 15} { 4x ^ { 2} } \times \frac { 28x } { 45}#?

2 Answers
smendyka
Aug 9, 2017

See a solution process below:

Explanation:

First, cancel common terms in the numerator and denominator:

#color(red)(cancel(color(black)(15)))/(color(blue)(cancel(color(black)(4)))color(green)(cancel(color(black)(x^2)))x) xx (color(blue)(cancel(color(black)(28)))7color(green)(cancel(color(black)(x))))/(color(red)(cancel(color(black)(45)))3) => 7/(3x)#

Aswin K.
Aug 9, 2017

#7/(3x)#

Explanation:

#15/(4x^2) *(28x)/45#

#=> (15*28x)/(4x^2*45)#

#=>(15*28x)/(4x*x*45)#

#=>(15*28cancelcolor(red)(x))/(4x*cancelcolor(red)(x)*45)#

#=> (15*28)/(4x*45)#

#=> (15*28)/(4x*3*15)#

#=> (cancelcolor(red)(15)*28)/(4x*3*cancelcolor(red)(15))#

#=> 28/(4x*3)#

#=> (4*7)/(4x*3)#

#=> (cancelcolor(red)(4)*7)/(cancelcolor(red)(4)x*3)#

#=> 7/(x*3)#

#=> 7/(3x)#

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