How do you solve #-\frac { 2} { 3} = \frac { 4x + 1} { 2x + 14}#?

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Answer 1 · 2017-08-10T17:12:43

#x = -31/16#

In this equation you have one fraction on each side.

#-2/3 = (4x+1)/(2x+14)#

In such a case you can cross-multiply to get rid of the fractions.

#3(4x+1) = -2(2x+14)#

#12x+3 = -4x-28" "larr# re-arrange the equation

#12x+4x = -28-3#

#16x = -31#

#x = -31/16#