How do you solve the following linear system: # 4x+9y=-53 , -6x-4y=32 #?

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Answer 1 · 2017-08-11T11:59:22

#4*(4x+9y)+9*(-6x-4y)=4*(-53)+9*32#

#16x+36y-54x-36y=-212+288#

#-38x=76#

#x=-2#

I put value of #x# into first equation,

#4*(-2)+9y=-53#

#9y-8=-53#

#9y=-45#

#y=-5#

1) I multiplied first equation with #4# and 2nd one with #9# for removing #y#.

2) I found #x#.

3) I put value of #x# into first one for finding #y#.