Question

An object moves along a curve has an acceleration of 5 m/s^2 at 30° with its velocity of 5 m/s at some instant . The radius of curvature of the path at that instant is ? a) 10 m b) 20 m c) 5 m d)15 m

Answer 1

a) 10 m

Explanation:

The normal component of the acceleration of a particle is given by `v^2/rho` Since here the normal component of the acceleration is `5 sin 30° = 2,5 ms^{-2}` the answer (a) follows