How many radial nodes are in a given atomic orbital as a function of #n# and #l#?

1 Answer
Aug 12, 2017

The total number of nodes in general is given by

#"Number of Nodes" = n - 1#,

where #n# is the principal quantum number, and #n = 1, 2, 3, 4, . . . #, given as the numerical coefficient for the orbital.

The angular momentum quantum number #l# specifies the number of angular nodes. Each #l# corresponds to a given orbital shape: #s, p, d, f, g, h, i, k, . . . #, and #l = 0, 1, 2, 3, 4, 5, 6, 7, . . . , n-1#. That is,

#"Number of Angular Nodes" = l#

Since there are only two types (radial, angular), it follows that:

#color(blue)(barul(|stackrel(" ")(" ""Number of Radial Nodes" = n - l - 1" ")|))#

CHALLENGE: Given the above radial density distribution, how many radial nodes are in each orbital? Can you show what it is, mathematically? If there were radial nodes in a radial density distribution, can you describe what you would see occur in the graph?