How do you subtract #\sqrt { 44a ^ { 2} b ^ { 3} } - \sqrt { 99a ^ { 2} b ^ { 3} }#?

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Answer 1 · 2017-08-13T06:23:28

#-ab sqrt(11b)#

#sqrt(44a^2b^3)-sqrt(99a^2b^3)#

First, we factorise the terms under the square roots.

#sqrt(2*2*11*a*a*b*b*b)-sqrt(3*3*11*a*a*b*b*b)#

Then, we take out of the square root all the squares.

#2ab sqrt(11b)-3ab sqrt(11b)#

Now, keeping #ab sqrt(11b)# as constant, subtract the other two terms.

#(2-3)ab sqrt(11b)#

#-1ab sqrt(11b)#

#-ab sqrt(11b)#