How do you solve #\frac { r - 8} { - 2} = \frac { 11- 4r } { 11}#?

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Answer 1 · 2017-08-13T16:32:59

r = 22

First, you multiply both sides by 22 to get rid of the denominator.

#(r-8)/-2=(11-4r)/11 ->#

#22*(r-8)/-2=22*(11-4r)/11 ->#

#-11(r-8)=2(11-4r)#

Next, you want to expand both sides of the equation.

#-11(r-8)=2(11-4r) ->#

#-11r+88=22-8r#

Then you want to put like terms together.

#-11r+88=22-8r ->#

#-11r+88-22+11r=22-8r-22+11r ->#

#66=3r#

Finally, solve for r.

#66=3r ->#

#66/3=(3r/3) ->#

#22=r#

If you have time, you can double check to make sure your answer makes sense by pugging it the value for r.

#(22-8)/-2=(11-4(22))/11 ->#

#(14)/-2=(11-88)/11 ->#

#(14)/-2=(-77)/11 ->#

#-7=-7# Which is a true statement, so #r=22# is correct.