How do you divide 4x ^ { 3} + 6x ^ { 2} - 23x - 15\div ( 3+ x )?
2 Answers
Aug 13, 2017
I a man assuming you mean to include brackets around the first four terms!
Aug 13, 2017
Explanation:
"one way is to use the divisor as a factor in the numerator"
"consider the numerator"
color(red)(4x^2)(x+3)color(magenta)(-12x^2)+6x^2-23x-15
=color(red)(4x^2)(x+3)color(red)(-6x)(x+3)color(magenta)(+18x)-23x-15
=color(red)(4x^2)(x+3)color(red)(-6x)(x+3)color(red)(-5)(x+3)color(magenta)(+15)-15
=color(red)(4x^2)(x+3)color(red)(-6x)(x+3)color(red)(-5)(x+3)+0
rArr(4x^3+6x^2-23x-15)/(x+3)=color(red)(4x^2-6x-5)