How do you graph the inequality #10x-8<22# on the coordinate plane?

1 Answer
Aug 16, 2017

See a solution process below:

Explanation:

First, solve the inequality for #x#:

#10x - 8 < 22#

#10x - 8 + color(red)(8) < 22 + color(red)(8)#

#10x - 0 < 30#

#10x < 30#

#(10x)/color(red)(10) < 30/color(red)(10)#

#(color(red)(cancel(color(black)(10)))x)/cancel(color(red)(10)) < 3#

#x < 3#

We can now graph this by drawing a vertical line at the point #3# on the x axis. The line will be dashes because this is a **"less than"88 inequality so does not contain the point #3# as part of the solution.

We will shade to the left of the line because, again, this is a "less than" inequality.

graph{x < 3}