Question

How do you graph the inequality `10x-8<22` on the coordinate plane?

Answer 1

See a solution process below:

Explanation:

First, solve the inequality for `x`:

`10x - 8 < 22`

`10x - 8 + color(red)(8) < 22 + color(red)(8)`

`10x - 0 < 30`

`10x < 30`

`(10x)/color(red)(10) < 30/color(red)(10)`

`(color(red)(cancel(color(black)(10)))x)/cancel(color(red)(10)) < 3`

`x < 3`

We can now graph this by drawing a vertical line at the point `3` on the x axis. The line will be dashes because this is a **"less than"88 inequality so does not contain the point `3` as part of the solution.

We will shade to the left of the line because, again, this is a "less than" inequality.

graph{x < 3}