How do you add #\frac { 6} { m - 4} - \frac { 4m } { m + 6}#?

1 Answer
Aug 17, 2017

Convert each term so that both terms have a common denominator then subtract the numerators to get
#color(white)("XXX")(2m-20)/(m^2+2m-24)#

Explanation:

#6/(m-4)-(4m)/(m+6)#

#color(white)("XXX")=6/(m-4)xx(m+6)/(m+6)-(4m)/(m+6)xx(m-4)/(m-4)#

#color(white)("XXX")=(6m-36)/(m^2+2m-24)-(4m-16)/(m^2+2m-24)#

#color(white)("XXX")=((6m-36)-(4m-16))/(m^2+2m-24)#

#color(white)("XXX")=(2m-20)/(m^2+2m-24)#