How do you find the distance between (10,19), (-13,9)?

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Answer 1 · 2017-08-17T12:08:01

Use # a^2 + b^2 = c^2 #

#c = 25.1#

Let the change in x be # a^2#
Let the change in y be # b^2#

The the square root of # c^2# = the distance

# a^2 = (19-9)^2#

#a^2 = 100#

# b^2 = ( 10- -13)^2#

# b^2 = 529#

# 100 + 529 = 629 #

# 629 = c^2#

square root of # 629 = c#

#c= sqrt629#

#c= 25.1#

Answer 2 · 2017-08-17T13:10:44

#=25.08#

The formula for the distance between two points is based on the Theorem of Pythagoras.

#|AB| = sqrt((x_2-x_1)^2 + (y_2-y_1)^2))#

We have the points #(10,19) and (-13,9)#

Distance = #sqrt((10-(-13))^2 +(19-9)^2)#

#= sqrt(23^2 +10^2)#

#=sqrt629#

#=25.08#