How do you write the standard form of a line given (1, 5), m = -3?

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Answer 1 · 2017-08-18T05:54:19

#y = -3x+8#

#3x+y =8" "larr #standard form

Use the point-slope formula: #y-y_1 = m(x-x_1)#

We have #(1,5) = (x_1,y_1) and m =-3#

#y-5=-3(x-1)#

#y-5 =-3x+3#

#y = -3x+3+5#

#y = -3x+8" "larr y#-intercept/gradient form.

#3x+y =8" "larr #standard form

#3x+y-8=0" "larr# general form

I hope that helps!