Given the function #f(x)=3(x+2)-4#, how do you solve for the inverse function when #x=2#?

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Answer 1 · 2017-08-19T03:27:45

#f^-1(2)=0#

#f(x)=3(x+2)-4#

Let's solve for the inverse of this function

#f(x)=3(x+2)-4#

#y=3(x+2)-4#

#x=3(y+2)-4#

#x+4=3(y+2)#

#(x+4)/3=y+2#

#(x+4)/3-2=y#

#f^-1(x) = (x+4)/3-2#

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Now let's solve for #x=2#

#f^-1(2)=((2)+4)/3-2#

#f^-1(2)=(6)/3-2#

#f^-1(2)=2-2#

#f^-1(2)=0#