Question

Question #d4f0b

Answer 1

Given that speed of rotating space station `v=12m"/"s`

If the radius of the orbit of rotation be `r` m, then centrifugal accelertion which is equal in magnitude of artificial accelartion due to gravity in the space station will be `g_a=v^2/r`

Now the acceleration due to gravity on earth `g_e=9.8m"/"s^2`

Now by the condition of the problem

`g_a=50% "of "g_e`

`=>v^2/r=50/100xxg_e`

`=>12^2/r=1/2xx9.8`

`=>r=(144xx2)/9.8~~29.4m`