Question #b4535
2 Answers
Aug 21, 2017
#y^2=4x+16#
Explanation:
Given-
focus
Directrix
Look at the diagram
#y^2=4ax#
Since vertex is away from the origin
#(y-k)^2=4a(x-h)#
Where (h,k) is vertex
From the given information
#h=-4#
#k=0#
#a=1#
Substitute these values
#(y-0)^2=4xx1xx(x-(-4))#
#y^2=4(x+4)#
#y^2=4x+16#
Aug 21, 2017
Explanation:
#"from any point "(x,y)" on the parabola"#
#"the distance to the focus and the directrix from this point"#
#"are equal"#
#color(blue)"using the distance formula then"#
#sqrt((x+3)^2+(y-0)^2)=|x+5|#
#color(blue)"squaring both sides"#
#(x+3)^2+y^2=(x+5)^2#
#rArrx^2+6x+9+y^2=x^2+10x+25#
#rArry^2-4x-16=0" is the equation"#