How do you graph the line #y + 3 = x + 6#?

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Answer 1 · 2017-08-21T12:00:13

See a solution process below:

First, solve the equation for two points and plot the points on the graph:

For #y = 3#:

#3 + 3 = x + 6#

#6 = x + 6#

#6 - color(red)(6) = x + 6 - color(red)(6)#

#0 = x + 0#

#0 = x#

#x = 0# or #(0, 3)#

For #x = 3#:

#y + 3 = 3 + 6#

#y + 3 = 9#

#y + 3 - color(red)(3) = 9 - color(red)(3)#

#y + 0 = 6#

#y = 6# or #(3, 6)#

graph{(x^2+(y-3)^2-0.05)((x-3)^2+(y-6)^2-0.05)=0 [-15, 15, -7.5, 7.5]}

Now, draw a line through the two points to graph the equation:

graph{(y-x-3)(x^2+(y-3)^2-0.05)((x-3)^2+(y-6)^2-0.05)=0 [-15, 15, -7.5, 7.5]}