Question

A silver bar 0.125 meter long is subjected to a temperature change from 200°C to 100°C. What will be the length of the bar after the temperature change?

Answer 1

I got `124.7mm`

Explanation:

The differece in length can be calculated as:

`DeltaL=alphaL_0DeltaT`

Where:
`L_0` is the original length;
`DeltaT` is the variation of temperature;
`alpha` is the coefficient of linear expansion .
From literature I got:

so, with your data:

`DeltaL=18.8xx10^-6*0.125(100-200)=2.35xx10^-4m=-0.235mm`

So the bar should shrink of `0.235mm` giving a new length of (changing in mm):

`125-0.235=124.7mm`