Question #b5600

1 Answer
Visual Physics
Aug 22, 2017

Total Kinetic Energy = Translational K.E + Rotational K.E = 0.35 J

Explanation:

Velocity #v=0.5 ms^-1#
Angular Velocity #omega = v/r = 0.5/0.2 = 2.5 rads^-1#
Moment of Inertia of Sphere #I = 2/5 MR^2 = 2/5(2kg)(0.2m)^2 = 0.032 kg m^2#

Total Kinetic Energy = Translational K.E + Rotational K.E = #1/2 MV^2 + 1/2 Iomega^2# = #1/2 (2 kg)(0.5ms^-1)^2 + 1/2 (0.032 kg m^2)(2.5 rads^-1)^2# = 0.35 J

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