How do you find the amplitude, period and phase shift for #y=3+5sin2(theta-pi)#?

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Answer 1 · 2017-08-23T18:15:41

Write in the standard form

#y = Asin(Btheta+C)+D#

#y = 5sin(2theta-2pi)+3#

The amplitude, A, is:

#A = 5#

The period, P, is:

#P = (2pi)/B#

#P = (2pi)/2#

#P = pi#

The phase shift, #phi#, is:

#phi = -C/B#

#phi = -(-2pi)/2#

#phi = pi#

The vertical shift, D, is:

#D = 3#