Question

How do you find the radius of a circle with equation `(x-5)^2+(y-3)^2=r^2` that contains the point at (5,1)?

Answer 1

The radius will measure `2` units.

Explanation:

Since `(x, y) = (5, 1)`, we have:

`(5 - 5)^2 + (1 - 3)^2 = r^2`

`0^2 + (-2)^2 = r^2`

`4 = r^2`

`r = 2`

Here is the corresponding graph.

graph{(x - 5)^2 + (y -3)^2 = 2^2 [-10, 10, -5, 5]}

Hopefully this helps!