Question

Question #4b2cd

Answer 1

`108`

Explanation:

Long method:

Let the first number be `x`. We know that, consecutive odd numbers have difference of `2`

So, the numbers are

`color(blue)(x,x+2,x+4,x+6,x+8,x+10,x+12,x+14,x+16`

It is stated that the third term (`x+4`) is equal to `9`

`rarrx+4=9`

`color(blue)(rarrx=9-4=5`

So, insert the value of `x` in the sequence to get the sum

`rarr(5)+(5+2)+(5+4)+(5+6)+(5+8)+(5+8)+(5+10)+(5+12)+(5+14)+(5+16)`

`rarr5+7+9+11+13+15+17+19+21`

`color(green)(rArr108`

Hope this helps!!!