Question

How do you solve `161= 4x + 3( 3x + 19)`?

Answer 1

See a solution process below: `x = 134/13`

Explanation:

First, expand the terms within the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

`161 = 4x + color(red)(3)(3x + 19)`

`161 = 4x + (color(red)(3) xx 3x) + (color(red)(3) xx 19)`

`161 = 4x + 9x + 57`

`161 = (4 + 9)x + 57`

`161 = 13x + 57`

Next, subtract `color(red)(57)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`161 - color(red)(57) = 13x + 57 - color(red)(57)`

`104 = 13x + 0`

`104 = 13x`

Now, divide each side of the equation by `color(red)(13)` to solve for `x` while keeping the equation balanced:

`104/color(red)(13) = (13x)/color(red)(13)`

`8 = (color(red)(cancel(color(black)(13)))x)/cancel(color(red)(13))`

`8 = x`

`x = 8`