How do you graph #2x + y = 8#?

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Answer 1 · 2017-08-26T14:35:11

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point:

For #x = 0#

#(2 * 0) + y = 8#

#0 + y = 8#

#y = 8# or #(0, 8)#

Second Point:

For #y = 0#

#2x + 0 = 8#

#2x = 8#

#(2x)/color(red)(2) = 8/color(red)(2)#

#x = 4# or #(4, 0#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-8)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x+y-8)(x^2+(y-8)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}