How do you divide #(3x ^ { 2} - 29x + 56) \div ( x - 7)#?
1 Answer
Aug 27, 2017
Explanation:
#"in this case factorise the numerator and cancel"#
#"common factors"#
#rArr((3x-8)cancel((x-7)))/cancel((x-7))#
#rArr"quotient "=3x-8," remainder "=0#
